## Size contest

Posted by ajay on June 1, 2006

Recently I was solving problems on Shpere online Judge and I found an interesting challange Size contest. The problems statement is that you are given a number n and a set of n integars, you have to calculate the sum of all the positive integars amongst those numbers. But the requirement is not to write the fast program but to write the shortest code for it. You might choose any language. Since I know only c/c++ and python so here is what i wrote in both of them respectively ..

# c++ code ..

#include<iostream>

main(){

int n,s=0,x;

for(std::cin>>n;n–;s+=x>0?x:0)

std::cin>>x;

std::cout<<s;

}

this code is 93 characters without spaces and newlines ..

now here is the python code ….

# python code ..

n=input()

y=0

for i in range(n):

z=input()

if z>0:

y=y+z

print y

this is 53 characters without spaces and new lines ..

can anybody help me reduce it to 70 ( in c/c++) and 26( in python ) .. which are the best codes for respective languages there or if not to that level at least reduce the code size .. 🙂 ..

## its me said

x=0

for i in range(input()):

x+=input()

print x

## ajay said

that was a better idea i guess .. but what if the user inputs a negative number .. we need not add that number in that case .. i think you hvnt checked that ..

## chaos said

c++:

move the statement

int n,s=0,x;

above the main..thn u can omit initialization of s i.e ur statement can be:

int n,s,x; //global ints initialized to 0 by default

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## _0_m3g4 said

x=0

for i in range(input()):

y=input()

x+=y*(y>0)

print x

#this is 49 chars 😉

## vinod said

#include

int n,x,s;main(){for(cin>>n;n–;s+=x>0?x:0)cin>>x;cout

## ajay said

x,n,s;main(){for(scanf(“%d”,&n);n–;s+=x>0?x:0)scanf(“%d”,&x);printf(“%d”,s);exit(0);}

// this is 87 chars .. but this time in c

## Stretch said

Great post with lots of imontrapt stuff.

## rocky said

A list of N numbers a1, a2, …, aN are given, find i and j, such that ai xor aj is maximized.can any body code a c++ proggramme for it..?????

## kushal7 said

#include

main(){int a,b,c=0;cin>>a;while(a–){cin>>b;b>0?c+=b:1;}cout<<c;}

// 84 chars